The enthalpy change for the following reaction is -136 kJ. Using bond energies, estimate the H-O...

The enthalpy change for the following reaction is -136 kJ. Using bond energies, estimate the H-O bond energy in H₂O₂(g).

H₂(g) + O₂(g) --> H₂O₂(g)

Solutions

Expert Solution

Bond energies, kJ per mol
H-H 436

OH-OH = ?

O-O 142

O=O 498

deltaH = Total energy in breaking bond - Total energy in formation of bonds

Bond energy of H2 is H-H (+436) and O2 is O=O (+498) = 934 kJ /mol

H2O2 is H-O-O-H

Total energy in formation of bonds = (-2*BE of O-H bond)

hence -136 = 934 - (2*BE of OH bond +142)

hence BE of O-H bond is 464 kJ/mol

queen_honey_blossom answered 1 year ago

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