In: Chemistry
The enthalpy change for the following reaction is
-136 kJ. Using bond energies, estimate the
H-O bond energy in
H2O2(g).
H2(g) + O2(g)
--> H2O2(g)
Bond energies, kJ per mol
H-H 436
OH-OH = ?
O-O 142
O=O 498
deltaH = Total energy in breaking bond - Total energy in formation of bonds
Bond energy of H2 is H-H (+436) and O2 is O=O (+498) = 934 kJ /mol
H2O2 is H-O-O-H
Total energy in formation of bonds = (-2*BE of O-H bond)
hence -136 = 934 - (2*BE of OH bond +142)
hence BE of O-H bond is 464 kJ/mol