Question

In: Statistics and Probability

Ten males and ten females were interviewed for a mid-level management position and their interview times...

Ten males and ten females were interviewed for a mid-level management position and their interview times were recorded in minutes . Shown below are descriptive statistics for the males and females. Your task is to determine of there was a significant difference in the average length of the interviews given to men and women.

Males. Females

N₁=10	N₂=10
M₁=36.5	M₂=37.5 (Upper-case M's ate used here in place of X-bar symbols for means

S²₁=25.5. S²₂=25.3 (These are the sample variances)

a. Give your obtained values of the test statistics=

b. give the critical values of the test statistics for the .05 level of significance=

c. Do the groups differ significantly? (Type YES or NO)

Expert Solution

Since s₁/s₂ = 5.05 / 5.03 = 1.00 (it lies between 0.5 and 2) we used the pooled variance.

The degrees of freedom used is n1 + n2 - 2 = 10 + 10 -2 = 18 (since pooled variance is used)

The Hypothesis:

H0:

Ha:

This is a Two tailed test.

The Decision Rule: If t observed is > t criticalor If t observed is < -t critical, Then Reject H0.

____________________________________

(a) The Test Statistic:

________________________

(b) The Critical Values: The critical value (2 tail) at = 0.05, df = 18, tcritical = +2.1 and -2.1

_________________________

(c) The Decision: Since t lies in between +2.1 and -2.1, We Fail To Reject H0

The Conclusion: Therefore NO, the groups do not differ significantly.

____________________________

orchestra answered 1 year ago

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