What is the critical value t* for a 99% confidence interval when n = 20?

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Expert Solution

Solution:
Given in the question
No. of sample = 20
Degree of freedom = No. of sample - 1 = 20-1 = 19
For 99% confidence interval, alpha = 0.01, alpha/2 = 0.005
So Critical value of t from t table at df = 19 and alpha/2=0.005
So t critical value = 2.861

orchestra answered 11 months ago

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