In: Statistics and Probability
Find the critical value t* for the following situations.
a) a 95% confidence interval based on df=19
b) a 90%confidence interval based on df=9
Solution :
Given that,
a)
Degrees of freedom = df = 19
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,19 = 2.093
The critical value t* 2.093
b)
Degrees of freedom = df = 9
At 90% confidence level the t is ,
= 1 - 90% = 1 - 0.90 = 0.1
/ 2 = 0.1 / 2 = 0.05
t /2,df = t0.05,9 = 1.833
The critical value t* 1.833