In: Statistics and Probability
The question is: Find the critical t-value that corresponds to 99% confidence. Assume 23 degrees of freedom (round to 3 decimal places as needed).
we can use the table values of t distributionto get the critical value of t that correponds to any given level of confidence for any given degree of freedom.
Here we have 99% confidence level and 23 degrees of freedom. In table values, for confidence interval we use the two sided values.
Below is the t table values and the corresponding value is pointed.
Hence, critical t-value that corresponds to 99% confidence with 23 degrees of freedom = 2.807