Question

A study of randomly selected Americans found that of 1,792 men, 244 had cardiovascular disease (CVD) and of 2,007 women, CVD was prevalent in 135 of them. Conduct a hypothesis test to see if CVD prevalence is higher among men than women in America. Let men be group 1 and women be group 2.

A. Write the hypotheses for this test.

B. What is the test statistic?

C. What is the p-value?

D. Using α = 0.05, decide whether or not to reject the null hypothesis.

E. Based on your decision, is there evidence that CVD prevalence is higher among men than women in America?

Answer 1

Solution:

Sample 1: Men

Sample 2: Women

From given values, Sample proportions can be calculated as,

A.

The following null and alternative hypotheses need to be tested:

This corresponds to a right-tailed test, for which a z-test for two population proportions needs to be conducted.

B.

The z-statistic is computed as follows:

C.

P-value is,

P(Z>7.074) = 0 ...Using Standard normal table

Hence, p-value = 0

D.

Since, P-value < 0.05 null hypothesis is rejected.

E. There evidence that CVD prevalence is higher among men than women in America.

Done