In: Statistics and Probability
A researcher hypothesizes that short term memory predicts
vocabulary knowledge. A random sample of Army recruits is selected
and given the digit span (a short term memory test) and vocabulary
subtests of the Wechsler Adult Intelligence Scale (WAIS). The data
are below. What can be concluded with an α of 0.05?
digit span | vocabulary |
---|---|
9 6 12 7 10 5 9 10 8 8 11 9 |
8 12 8 11 7 11 7 9 10 9 8 10 |
a) What is the appropriate statistic?
---Select--- na Correlation Slope Chi-Square
Compute the statistic selected above:
b) Compute the appropriate test statistic(s) to
make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
p-value = ; Decision: ---Select---
Reject H0 Fail to reject H0
c) Using the SPSS results,
compute the corresponding effect size(s) and indicate
magnitude(s).
If not appropriate, input and/or select "na" below.
Effect size = ; ---Select--- na trivial
effect small effect medium effect large effect
d) Make an interpretation based on the
results.
Better short term memory significantly predicts more vocabulary.Better short term memory significantly predicts less vocabulary. Short term memory does not significantly predict vocabulary.
Coefficientsa | ||||||
Model | Unstandardized Coefficients | Standardized Coefficients | t | Sig. | ||
B | Std. Error | Beta | ||||
1 | (Constant) | 14.664 | 1.437 | 10.207 | .000 | |
digit_span | -.634 | .162 | -.778 | -3.920 | .003 |
a) What is the appropriate statistic?
-Ans: Slope
The corresponding test statistic selected above from the above
table is -3.920.
b) Compute the appropriate test statistic(s) to
make a decision about H0.
Hypothesis:
Null Hypothesis: Slope=0
Alternative Hypothesis: Slope does not equal to zero.
p-value = 0.003 ; Decision: Reject H0 .
c) Using the SPSS results,
compute the corresponding effect size(s) and indicate
magnitude(s).
If not appropriate, input and/or select "na" below.
ANOVAb | ||||||
Model | Sum of Squares | df | Mean Square | F | Sig. | |
1 | Regression | 17.973 | 1 | 17.973 | 15.369 | .003a |
Residual | 11.694 | 10 | 1.169 | |||
Total | 29.667 | 11 |
Effect size = 17.973/29.667=0.6058 ; large effect
d) Make an interpretation based on the
results.
Ans: Better short term memory significantly predicts more vocabulary.