In: Statistics and Probability
A university lecturer in History hypothesizes that more time
studying predicts better exam performance. Before the next exam,
the lecture asks students in the class the average amount of time
(in minutes) they spend in the library per day. The data are below.
What can be concluded with α = 0.05?
time | exam |
---|---|
41 25 48 58 66 81 95 101 121 97 81 111 |
75 75 69 72 63 60 66 57 60 70 65 65 |
a) What is the appropriate statistic?
---Select--- na Correlation Slope Chi-Square
Compute the statistic selected above:
b) Compute the appropriate test statistic(s) to
make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
Critical value = ; Test statistic =
Decision: ---Select--- Reject H0 Fail to reject H0
c) Compute the corresponding effect size(s) and
indicate magnitude(s).
If not appropriate, input and/or select "na" below.
Effect size = ; ---Select--- na trivial
effect small effect medium effect large effect
d) Make an interpretation based on the
results.
Students who spend more time studying have better exam performance.Students who spend more time studying have worse exam performance. Students time studying does not predict exam performance.
a) What is the appropriate statistic?
Correlation
(b)
Following table shows the calculations:
Time, X | Exam, Y | X^2 | Y^2 | XY | |
41 | 75 | 1681 | 5625 | 3075 | |
25 | 75 | 625 | 5625 | 1875 | |
48 | 69 | 2304 | 4761 | 3312 | |
58 | 72 | 3364 | 5184 | 4176 | |
66 | 63 | 4356 | 3969 | 4158 | |
81 | 60 | 6561 | 3600 | 4860 | |
95 | 66 | 9025 | 4356 | 6270 | |
101 | 57 | 10201 | 3249 | 5757 | |
121 | 60 | 14641 | 3600 | 7260 | |
97 | 70 | 9409 | 4900 | 6790 | |
81 | 65 | 6561 | 4225 | 5265 | |
111 | 65 | 12321 | 4225 | 7215 | |
Total | 925 | 797 | 81049 | 53319 | 60013 |
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(b)
(c)
Since results are not significant so effect size is not necessary.
Effect size =na
(d)
Students who spend more time studying have worse exam performance.