In: Math
A researcher hypothesizes that the percentage of Ball State University students who sleep 8 or more hours per night is lower than the general population of adults. Previous research has found that 40% of adults sleep 8 hours or more per night. In a recent survey of Ball State students, the researcher found that 38 students reported sleeping 8 hours or more and 82 students reported sleeping less than 8 hours. Do the Ball State student sleep habits differ from those expected of the general population of adults?
a. Using Excel, conduct a Chi-square goodness of fit test on these data.
b. Report the results in a textbox. Be sure to provide both a statistical and research conclusion.
Research shows 40% of adults sleep 8 hours or
more
Thus 60% of adults sleep less than 8 hours
n = 38 + 82 = 120 Number of students
studied
Null and alternative hypothesis are
Ho : There is no difference between Ball State student
sleep habits and expected of general population
Ha : There is a difference between Ball State student
sleep habits and expected of general population
We find the expected frequency by
multiplying each probability with total students
studied(120)
Category | Observed Freq (O) | Expected Freq (E ) |
8 hours or more sleep | 38 | 48 |
Less than 8 hours sleep | 82 | 72 |
a) Using Excel function chisq.test we get the
p-value for the test
p-value = CHISQ.TEST(observed frequencies,
expected frequencies)
p-value = 0.0624
We assume
α = 0.05 that is 5% significance
level
0.0624 > 0.05
Since p-value > α, we do not reject the
null hypothesis
b) Results
p-value = 0.0624
Decision : Do not Reject the null
hypothesis
Conclusion
(Statistical) :
There does not exist sufficient statistical
evidence at 5% level of significance
to show that there is a difference between Ball State
student sleep habits and expected of general population
Conclusion
(Research) :
Ball State student sleep habits do not differ
from those expected of the general population of adults