Question

In: Statistics and Probability

A college dean is interested in the exam performance of students in a History course. After...

A college dean is interested in the exam performance of students in a History course. After the final exam, students are randomly selected from three different section of the History course. What can be conclude with an α of 0.01? The data are below.

section 1 section 2 section 3
82
68
74
65
41
75
64
77
40
78
69
90
82
82
77
75
82
81
91
70
90
82
94
81
87
82
72
77
81
87
67
86
77


a) What is the appropriate test statistic?
---Select--- na one-way ANOVA within-subjects ANOVA two-way ANOVA

b) Compute the appropriate test statistic(s) to make a decision about H0.
critical value =  ; test statistic =  
Decision:  ---Select--- Reject H0 Fail to reject H0

c) Compute the corresponding effect size(s) and indicate magnitude(s).
η2 =  ;  ---Select--- na trivial effect small effect medium effect large effect

d) Make an interpretation based on the results.

At least on section differs on the final exam.None of the sections differ on the final exam.    


e) Conduct Tukey's Post Hoc Test for the following comparisons:
1 vs. 3: difference =  ; significant:  ---Select--- Yes No
1 vs. 2: difference =  ; significant:  ---Select--- Yes No

f) Conduct Scheffe's Post Hoc Test for the following comparisons:
2 vs. 3: test statistic =  ; significant:  ---Select--- Yes No
1 vs. 3: test statistic =  ; significant:  ---Select--- Yes No

Solutions

Expert Solution

a) Appropriate test statistic = one-way ANOVA

b)

Section 1 Section 2 Section 3 Total
Sum 733 902 891 2526
Count 11 11 11 33
Mean, Sum/n 66.6364 82 81
Sum of square, Ʃ(xᵢ-x̅)² 1980.5455 428 576

Number of treatment, k = 3

Total sample Size, N = 33

df(between) = k-1 = 2

df(within) = N-k = 30

df(total) = N-1 = 32

SS(between) = (Sum1)²/n1 + (Sum2)²/n2 + (Sum3)²/n3 - (Grand Sum)²/ N = 1625.6364

SS(within) = SS1 + SS2 + SS3 = 2984.5455

SS(total) = SS(between) + SS(within) = 4610.1818

MS(between) = SS(between)/df(between) = 812.8182

MS(within) = SS(within)/df(within) = 99.4848

Critical value Fc = F.INV.RT(0.01, 2, 30) = 5.390

Test statistic:

F = MS(between)/MS(within) = 8.1703

Decision: Reject H0

ANOVA
Source of Variation SS df MS F Critical value
Between Groups 1625.6364 2 812.8182 8.1703 5.390
Within Groups 2984.5455 30 99.4848
Total 4610.1818 32

c) ɳ² = SS(between)/SS(total) = 1625.6364/4610.1818 = 0.3526

Effect size, large

d) Interpretation based on the results.

At least on section differs on the final exam.

e) Tukey's Post Hoc Test:

At α = 0.01, k = 3, N-K = 30, Q value = 4.45

Comparison Absolute Diff. = |xi - xj| Critical Range = Q* √(MSwithin/n) Significant
x̅1-x̅3 14.3636 13.3827 Yes
x̅1-x̅2 15.3636 13.3827 Yes

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