In: Statistics and Probability
Consider the following data drawn independently from normally
distributed populations: (You may find it useful to
reference the appropriate table: z table
or t table)
x−1x−1 = 25.7 | x⎯⎯2x¯2 = 30.6 |
σ12 = 98.2 | σ22 = 87.4 |
n1 = 20 | n2 = 25 |
a. Construct the 95% confidence interval for the
difference between the population means. (Negative values
should be indicated by a minus sign. Round all intermediate
calculations to at least 4 decimal places and final answers to 2
decimal places.)
Confidence internval is _____ to ____.
Consider the following competing hypotheses and accompanying
sample data drawn independently from normally distributed
populations. (You may find it useful to reference the
appropriate table: z table or t
table)
H0: μ1 −
μ2 = 0
HA: μ1 −
μ2 ≠ 0
x−1x−1 = 51 | x−2x−2 = 60 |
σ1 = 13.00 | σ2 = 1.64 |
n1 = 25 | n2 = 25 |
a-1. Calculate the value of the test statistic.
(Negative values should be indicated by a minus sign. Round
all intermediate calculations to at least 4 decimal places and
final answer to 2 decimal places.)
Test statistic:
Researchers at The Wharton School of Business have found that men and women shop for different reasons. While women enjoy the shopping experience, men are on a mission to get the job done. Men do not shop as frequently, but when they do, they make big purchases like expensive electronics. The accompanying table shows the amount spent (in $) over the weekend by 40 men and 60 women at a local mall. The Excel file is also provided. (You may find it useful to reference the appropriate table: z table or t table)
Spending by Men | Spending by Women | Spending by Men | Spending by Women |
85 | 90 | 87 | 38 |
102 | 79 | 92 | 66 |
139 | 71 | 92 | 100 |
90 | 119 | 72 | 57 |
89 | 90 | 97 | 59 |
52 | 180 | 83 | 89 |
49 | 88 | 118 | 95 |
140 | 56 | 108 | 37 |
90 | 110 | 104 | 86 |
64 | 82 | 110 | 62 |
96 | 64 | 66 | |
132 | 129 | 129 | |
117 | 28 | 119 | |
88 | 13 | 76 | |
92 | 140 | 75 | |
105 | 62 | 101 | |
95 | 32 | 85 | |
119 | 220 | 68 | |
118 | 72 | 67 | |
124 | 90 | 36 | |
131 | 80 | 90 | |
113 | 56 | 99 | |
124 | 82 | 64 | |
71 | 56 | 54 | |
115 | 88 | 86 | |
95 | 104 | 79 | |
102 | 54 | 82 | |
94 | 108 | 65 | |
111 | 86 | 110 | |
85 | 88 | 69 | |
Click here for the Excel Data File
Let µ1 represent the population mean amount
spent by men and µ2 represent the population
mean amount spent by women.
a. Specify the competing hypotheses that determine
if the mean amount spent by men is more than that by
women.
H0: μ1 − μ2 = 0; HA: μ1 − μ2 ≠ 0
H0: μ1 − μ2 ≥ 0; HA: μ1 − μ2 < 0
H0: μ1 − μ2 ≤ 0; HA: μ1 − μ2 > 0
b. Calculate the value of the test statistic.
Assume that the population variances are unknown but equal.
(Round intermediate calculations to at least 4 decimal
places and final answer to 2 decimal places.)
test statistic:
using excel>addin>phstat>two sample test
we have
Pooled-Variance t Test for the Difference Between Two Means | ||||
(assumes equal population variances) | ||||
Data | Confidence Interval Estimate | |||
Hypothesized Difference | 0 | for the Difference Between Two Means | ||
Level of Significance | 0.05 | |||
Population 1 Sample | Data | |||
Sample Size | 20 | Confidence Level | 95% | |
Sample Mean | 25.7 | |||
Sample Standard Deviation | 9.91 | Intermediate Calculations | ||
Population 2 Sample | Degrees of Freedom | 43 | ||
Sample Size | 25 | t Value | 2.0167 | |
Sample Mean | 30.6 | Interval Half Width | 5.8086 | |
Sample Standard Deviation | 9.349 | |||
Confidence Interval | ||||
Intermediate Calculations | Interval Lower Limit | -10.7086 | ||
Population 1 Sample Degrees of Freedom | 19 | Interval Upper Limit | 0.9086 | |
Population 2 Sample Degrees of Freedom | 24 | |||
Total Degrees of Freedom | 43 | |||
Pooled Variance | 92.1778 | |||
Standard Error | 2.8803 | |||
Difference in Sample Means | -4.9000 | |||
t Test Statistic | -1.7012 | |||
Two-Tail Test | ||||
Lower Critical Value | -2.0167 | |||
Upper Critical Value | 2.0167 | |||
p-Value | 0.0961 | |||
Do not reject the null hypothesis |
a ) The confidence interval is -10.71 to
0.91
Ans 2 )
H0: μ1 − μ2 = 0
HA: μ1 − μ2 ≠ 0
using excel>addin>phstat>two sample test
we have
Pooled-Variance t Test for the Difference Between Two Means | |
(assumes equal population variances) | |
Data | |
Hypothesized Difference | 0 |
Level of Significance | 0.05 |
Population 1 Sample | |
Sample Size | 25 |
Sample Mean | 51 |
Sample Standard Deviation | 13 |
Population 2 Sample | |
Sample Size | 25 |
Sample Mean | 60 |
Sample Standard Deviation | 1.64 |
Intermediate Calculations | |
Population 1 Sample Degrees of Freedom | 24 |
Population 2 Sample Degrees of Freedom | 24 |
Total Degrees of Freedom | 48 |
Pooled Variance | 85.8448 |
Standard Error | 2.6206 |
Difference in Sample Means | -9.0000 |
t Test Statistic | -3.4343 |
Two-Tail Test | |
Lower Critical Value | -2.0106 |
Upper Critical Value | 2.0106 |
p-Value | 0.0012 |
Reject the null hypothesis | |
a-1. the value of the test statistic t = -3.43
Ans3 ) Researchers at The Wharton School of Business have found
that men and women shop for different reasons. While women enjoy
the shopping experience, men are on a mission to get the job done.
Men do not shop as frequently, but when they do, they make big
purchases like expensive electronics. The accompanying table shows
the amount spent (in $) over the weekend by 40 men and 60 women at
a local mall. The Excel file is also provided. (You may
find it useful to reference the appropriate table: z table
or t table)
Click here for the Excel Data File
Let µ1 represent the population mean amount spent by men
and µ2 represent the population mean amount spent by
women.
a. Specify the competing hypotheses that determine
if the mean amount spent by men is more than that by women.
H0: μ1 − μ2 ≤ 0; HA: μ1 − μ2 > 0
usig excel we have
Pooled-Variance t Test for the Difference Between Two Means | |
(assumes equal population variances) | |
Data | |
Hypothesized Difference | 0 |
Level of Significance | 0.05 |
Population 1 Sample | |
Sample Size | 40 |
Sample Mean | 99.75 |
Sample Standard Deviation | 21.35386 |
Population 2 Sample | |
Sample Size | 60 |
Sample Mean | 82.1 |
Sample Standard Deviation | 33.86899 |
Intermediate Calculations | |
Population 1 Sample Degrees of Freedom | 39 |
Population 2 Sample Degrees of Freedom | 59 |
Total Degrees of Freedom | 98 |
Pooled Variance | 872.0704 |
Standard Error | 6.0280 |
Difference in Sample Means | 17.6500 |
t Test Statistic | 2.9280 |
Upper-Tail Test | |
Upper Critical Value | 1.6606 |
p-Value | 0.0021 |
Reject the null hypothesis |
b. the value of the test statistic = 2.93