In: Statistics and Probability
In testing the hypothesis H0: μ = 800 vs. Ha: μ ≠ 800. A sample of size 40 is chosen. the sample mean was found to be 812.5 with a standard deviation of 25, then the of the test statistic is:
Z=0.0401 |
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Z=-3.16 |
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Z=3.16 |
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Z=12.5 |
In a sample of 500 voters, 400 indicated they favor the incumbent governor. The 95% confidence
interval of voters not favoring the incumbent is
0.782 to 0.818 |
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0.120 to 0.280 |
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0.765 to 0.835 |
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0.165 to 0.235 |
A Type II error is committed if we make:
a correct decision when the null hypothesis is false |
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correct decision when the null hypothesis is true |
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incorrect decision when the null hypothesis is false |
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incorrect decision when the null hypothesis is true |
What is the value of z α/2 for an 85% confidence interval?
1.44 |
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.385 |
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.0279 |
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.19 |
A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25. The upper limit of a 95% confidence interval for the population mean would equal:
77.769 |
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72.231 |
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72.727 |
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77.273 |
Here we have to test that
where
n = sample size = 40
Sample mean =
Sample standard deviation = s = 25
Here population standard deviation is not known but sample size n is large, n = 40 > 30
So we use z test.
Test statistic:
z = 3.16 (Round to 2 decimal)
Test statistic = z = 3.16
n = number of voters selected randomly = 500
x = number of voters not favor the incumbent governor = 500 - 400 = 100
Sample proportion:
= proportion of voters not favoring the incumbent = 0.2
95% Confidence interval of voters not favoring the incumbent is
where zc is z critical value for (1+c)/2 = (1+0.95)/2 = 0.975
zc = 1.96 (From statistucal table of z values)
0.165 < p < 0.235
95% Confidence interval of voters not favoring the incumbent is (0.165, 0.235)
A Type II error is committed if we make:
incorrect decision when the null hypothesis is false.
Confidence level = c = 0.85
alpha = 1 - c = 1 - 0.85 = 0.15
alpha/2 = 0.15/2 = 0.075
z for 0.075 is z = -1.44
z for (1-0.075) = 0.925 is z = 1.44