In: Statistics and Probability
let us consider the null and alternative hypothesis is
Ho:the difference between men and women in illness attack rate is not significant
Ha: the difference between men and women in illness attack rate is significant
Chi-Square Test | ||||||
Observed Frequencies(O) | ||||||
Attack rate | Calculations | |||||
Gender | ill | not ill | Total | fo-fe | ||
Men | 13 | 39 | 52 | -6 | 6 | |
Women | 25 | 27 | 52 | 6 | -6 | |
Total | 38 | 66 | 104 | |||
Expected Frequencies€ | ||||||
Attack rate | ||||||
Gender | ill | not ill | Total | (fo-fe)2/fe | ||
Men | = = 19 | = =33 | 52 | 1.894737 | 1.090909 | |
Women | =19 | =33 | 52 | 1.894737 | 1.090909 | |
Total | 38 | 66 | 104 | |||
Data | ||||||
Level of Significance | 0.05 | |||||
Number of Rows | 2 | |||||
Number of Columns | 2 | |||||
Degrees of Freedom | 1 | |||||
Results | ||||||
Critical Value | 3.841459 | |||||
Chi-Square Test Statistic | 5.971292 | |||||
p-Value | 0.014541 | |||||
Reject the null hypothesis |
Since p value is 0.0145 which is less than 0.05 so we reject Ho and conclude that the difference between men and women in illness attack rate is significant