In: Chemistry
Consider the system: A (aq) → B (aq) at 283 K where ΔGoform A = -11.5 kJ/mol and ΔGoform B = -13.3 kJ/mol. Calculate the concentration of A at equilibrium when 2.01 mol of A and 1.39 mol of B are mixed in water to form exactly one liter of solution.
A (aq) → B (aq)
ΔG0 = ΔG0f products - ΔG0f reactans
=-13.3-(-11.5) = -1.8Kj/mole = -1800J/mole
ΔG0 = -RTlnk
-1800 = -8.314*298*2.303logK
-1800 = -5705.84logK
logK = -1800/-5705.84
logK = 0.315
K = 10^0.315
K = 2.0654
concentration of A [A] = no of moles/volume in L
= 2.01/1 = 2.01M
concentration of B [B] = no of moles/volume in L
= 1.39/1 = 1.39M
A (aq) → B (aq)
I 2.01 1.39
C -x +x
E 2.01-x 1.39+x
Kc = [B]/[A]
2.0654 = 1.39+x/2.01-x
2.0654*(2.01-x) = 1.39+x
x = 0.9
[A] = 2.01-x = 2.01-0.9 = 1.11M
the concentration of A at equilibrium = 1.11M