Question

In: Chemistry

Consider the system: A (aq) → B (aq) at 283 K where ΔGoform A = -11.5...

Consider the system: A (aq) → B (aq) at 283 K where ΔGoform A = -11.5 kJ/mol and ΔGoform B = -13.3 kJ/mol. Calculate the concentration of A at equilibrium when 2.01 mol of A and 1.39 mol of B are mixed in water to form exactly one liter of solution.

Solutions

Expert Solution

A (aq) → B (aq)

ΔG0    = ΔG0f products - ΔG0f reactans

=-13.3-(-11.5)     = -1.8Kj/mole     = -1800J/mole

ΔG0      = -RTlnk

-1800    = -8.314*298*2.303logK

-1800    = -5705.84logK

logK        = -1800/-5705.84

logK           = 0.315

K              = 10^0.315

K              = 2.0654

concentration of A [A]   = no of moles/volume in L

                                         = 2.01/1 = 2.01M

concentration of B [B]   = no of moles/volume in L

                                         = 1.39/1 = 1.39M

                 A (aq) → B (aq)

I               2.01        1.39

C             -x                +x

E             2.01-x        1.39+x

              Kc   = [B]/[A]

              2.0654 = 1.39+x/2.01-x

             2.0654*(2.01-x) = 1.39+x

                  x   = 0.9

          [A]    = 2.01-x    = 2.01-0.9   = 1.11M

the concentration of A at equilibrium   = 1.11M


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