In: Chemistry
5Fe^2+ (aq) + MnO4^-(aq) + 8H^+ ------------------> Mn^2+(aq) + 5Fe^3+ (aq) + 4H2O(l)
no of moles of Fe^2+ = molarity * volume in L
= 0.5*0.1 = 0.05 moles
no of moles of MnO4^- = molarity * volume in L
= 0.1*0.1 = 0.01 moles
5Fe^2+ (aq) + MnO4^-(aq) + 8H^+ ------------------> Mn^2+(aq) + 5Fe^3+ (aq) + 4H2O(l)
5 moles of Fe^2+ react with 1 moles of MnO4^-
0.05 moles of Fe^2+ react with = 1*0.05/5 = 0.01 moles of MnO4^-
0.05 moles of Fe^2+ is reacted