Question

What is the quantity of Fe2+ ion reacting in moles? 100ml of a 0.500 M solution of Fe2+ is added to 100ml of a 0.100 M solution of MnO4-. (Mol)?

Answer 1

   5Fe^2+ (aq) + MnO4^-(aq) + 8H^+ ------------------> Mn^2+(aq) + 5Fe^3+ (aq) + 4H2O(l)

no of moles of Fe^2+ = molarity * volume in L

                                  = 0.5*0.1 = 0.05 moles

no of moles of MnO4^-   = molarity * volume in L

                                         = 0.1*0.1 = 0.01 moles

5Fe^2+ (aq) + MnO4^-(aq) + 8H^+ ------------------> Mn^2+(aq) + 5Fe^3+ (aq) + 4H2O(l)

5 moles of Fe^2+ react with 1 moles of MnO4^-

0.05 moles of Fe^2+ react with = 1*0.05/5 = 0.01 moles of MnO4^-

0.05 moles of Fe^2+ is reacted