In: Chemistry
Calculate the amount (in mL) of 0.2023 M NaOH needed to reach the end point of titration, of 0.7246 g hydrocinnamic acid. Note: in lab, the equivalence point where pKa=pH would be 1/2 of the amount you calculate for this question. Answer:
C6H5-CH2-CH2-COOH + NaOH ---> C6H5-CH2-CH2-COONa +
H2O
1 mole hydrocinnamic acid = 1 mole NaOH
NO of mole of hydrocinnamic acid = 0.7246/150.17 = 0.0048 mole
NO of mole of NaOH required to reach equivalence point = 0.0048 mole
volume of 0.2023 M NaOH required = n/M
= 0.0048/0.2023
= 0.0237 L
= 23.7 ml