Calculate the amount (in mL) of 0.2023 M NaOH needed to reach the end point of...

Calculate the amount (in mL) of 0.2023 M NaOH needed to reach the end point of titration, of 0.7246 g hydrocinnamic acid. Note: in lab, the equivalence point where pKa=pH would be 1/2 of the amount you calculate for this question. Answer:

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Expert Solution

C6H5-CH2-CH2-COOH + NaOH ---> C6H5-CH2-CH2-COONa + H2O

1 mole hydrocinnamic acid = 1 mole NaOH

NO of mole of hydrocinnamic acid = 0.7246/150.17 = 0.0048 mole

NO of mole of NaOH required to reach equivalence point = 0.0048 mole

volume of 0.2023 M NaOH required = n/M

= 0.0048/0.2023

= 0.0237 L

= 23.7 ml

queen_honey_blossom answered 1 year ago

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