Question

In: Chemistry

Calculate the amount (in mL) of 0.2023 M NaOH needed to reach the end point of...

Calculate the amount (in mL) of 0.2023 M NaOH needed to reach the end point of titration, of 0.7246 g hydrocinnamic acid. Note: in lab, the equivalence point where pKa=pH would be 1/2 of the amount you calculate for this question. Answer:

Solutions

Expert Solution


C6H5-CH2-CH2-COOH + NaOH ---> C6H5-CH2-CH2-COONa + H2O

1 mole hydrocinnamic acid = 1 mole NaOH

NO of mole of hydrocinnamic acid = 0.7246/150.17 = 0.0048 mole

NO of mole of NaOH required to reach equivalence point = 0.0048 mole

volume of 0.2023 M NaOH required = n/M

                                  = 0.0048/0.2023

                                  = 0.0237 L

                                  = 23.7 ml


Related Solutions

1. Calculate the volume in milliliters (mL) of a 6.00 M NaOH solution needed to make...
1. Calculate the volume in milliliters (mL) of a 6.00 M NaOH solution needed to make 5.00 x 102 mL of a 0.100 M NaOH solution. (Recall that M = molar = mol/L, and show all your work). 2. An approximately 0.1 M NaOH solution was standardized with KHP by titration to a phenolphthalein endpoint. From the following data, calculate the average molarity of the NaOH. The molar mass of KHP is 204.22 g/mol. Trial 1 Trial 2 Mass of...
Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M...
Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M solution of the monoprotic acid HCl. __________ mL NaOH
1/ Calculate the volume of 0.280-M NaOH solution needed to completely neutralize 27.4 mL of a...
1/ Calculate the volume of 0.280-M NaOH solution needed to completely neutralize 27.4 mL of a 0.560-M solution of the monoprotic acid HBr. 2/ To determine the molar mass of an organic acid, HA, we titrate 1.047 g of HA with standardized NaOH. Calculate the molar mass of HA assuming the acid reacts with 37.17 mL of 0.469 M NaOH according to the equation HA(aq) + NaOH(aq) → NaA(aq) + H2O(ℓ) 3/ 2 NaBH4(aq) + H2SO4(aq) → 2 H2(g) +...
In a titration 34.20 mL HI, 21.78 mL of 0.250 M LiOH was needed to reach...
In a titration 34.20 mL HI, 21.78 mL of 0.250 M LiOH was needed to reach the equivalence point. a.) What is the reaction equation for this reaction? b.) How many moles of LiOH were added during the titration? c.) How many moles of HI were present in the original sample? d.) What was the HI concentration in the original sample? Please show all steps!!! This is for my test's study guide
1) Calculate the amount of 1.50 M Na2CO3 needed to react completely with 25.0 mL of...
1) Calculate the amount of 1.50 M Na2CO3 needed to react completely with 25.0 mL of 0.500 M CaCl2. 2) Calculate the theoretical yield of chalk (calcium carbonate) for each reaction (#1 & #2)—show all calculations. For reaction #1 CaCl2 should be limiting and for reaction #2 Na2CO3 should be limiting. You need to figure out how much sodium carbonate solution you will use in your experiment Na2CO3(aq) + CaCl2(aq) àCaCO3(s) + 2NaCl(aq)  (molecular equation) CO32– (aq)  +  Ca2+(aq)  àCaCO3(s)   (net ionic equation) Limiting reactant(determining...
Find the pH and the volume (mL) of 0.487 M HNO3 needed to reach the equivalence...
Find the pH and the volume (mL) of 0.487 M HNO3 needed to reach the equivalence point in the titration of 2.65 L of 0.0750 M pyridine (C5H5N)?
Find the volume (mL) and the pH of 0.135 M HCl needed to reach the equivalence...
Find the volume (mL) and the pH of 0.135 M HCl needed to reach the equivalence point(s) in titrations of the following. (You need to find the pH at the equivalence point, not the initial pH of the solution. (a) 50.8 mL of 0.272 M NH3 (b) 11.8 mL of 1.76 M CH3NH2
Calculate the volume (in mL) of 0.170 M NaOH that must be added to 259 mL...
Calculate the volume (in mL) of 0.170 M NaOH that must be added to 259 mL of 0.0419 M 3-(N-Morpholino)propanesulfonic acid (MOPS) to give the solution a pH of 7.55. The pKa of MOPS = 7.18.
For the titration of 25.00 mL of 0.1000 M HCl with 0.1000 M NaOH, calculate the...
For the titration of 25.00 mL of 0.1000 M HCl with 0.1000 M NaOH, calculate the pH of the reaction mixture after each of the following total volumes of base have been added to the original solution. (Remember to take into account the change in total volume.) Select a graph showing the titration curve for this experiment. (a) 0 mL (b) 10.00 mL (c) 24.90 mL (d) 24.99 mL (e) 25.00 mL (f) 25.01 mL (g) 25.10 mL (h) 26.00...
For the titration of 20.00 mL of 0.150 M HF with0.250 M NaOH, calculate: a) the...
For the titration of 20.00 mL of 0.150 M HF with0.250 M NaOH, calculate: a) the initial pH;Ka= 6.6 x 10^-4 b) the pH when the neutralization is 25% complete c) the pH when the neutralization is 50% complete d) the pH when the neutralization is 100% complete
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT