When a bicyclic (or even polycyclic) compound such as ß-Naphthol is being brominated via EAS, how...

When a bicyclic (or even polycyclic) compound such as ß-Naphthol is being brominated via EAS, how do I determine the locations on the molecule that will be substituted with bromine in the final product. This has to do with resonance structures of the molecule and O/P vs M directing effects of the substituent already on the ring before bromination. I'm just having trouble making the connection. Does it differ in any way compare to a molecule with only one ring, like phenol? An example and clarification would be great! Thanks!

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Expert Solution

there fore orientation effect of -OH group in phenol or naphthol is same which is ortho and para.

with 1- napthol the positions for substitution by electrophile are different which will predicted by drawing rsonance forms.

queen_honey_blossom answered 1 year ago

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