In: Statistics and Probability
A researcher found that there is an increase in undergraduate students doing part- time jobs to partially support their expenses. It is assumed that 55% of UWindsor students do part time jobs in this current year. The researcher randomly selected 150 UWindsor students and checked whether they work part-time jobs. Answer the following based on this data:
Find the probability that more than 90 students of these 150 selected said that they do part-time jobs.
Find the probability that less than 80 students of these 150 selected said that they do part-time jobs.
1) probability that more than 90 students of these 150 selected said that they do part-time jobs = 0.1092
2) probability that less than 80 students of these 150 selected said that they do part-time jobs=0.3405
Working:
We have given below information
P0=0.55 =% of UWindsor students do part time jobs in this current year.
n=150
1)
Find the probability that more than 90 students of these 150 selected said that they do part-time jobs.
We have to find p(P>90/150)=p(P>0.6)
We know that
z=(P-P0)/sqrt(P0*(1-P0)/n) ~ N(0,1)
p(P>0.6) = p(z>(0.6-0.55)/sqrt(0.55*(1-0.55)/150))
p(Z>1.2309)
=0.1092
2)
Find the probability that less than 80 students of these 150 selected said that they do part-time jobs
We have to find p(P<80/150)
=p(P<0.5333)
= p(z<(0.5333-0.55)/sqrt(0.55*(1-0.55)/150))
=p(Z<-0.4111)
=0.3405
Answer
1) probability that more than 90 students of these 150 selected said that they do part-time jobs = 0.1092
2) probability that less than 80 students of these 150 selected said that they do part-time jobs=0.3405