A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,...

A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon, 6.72% hydrogen and 53.28% oxygen. What is the empirical and molecular formulas of the molecule? (C=12.01 g/mol, H=1.01 g/mol, and O= 16.00 g/mol)

I know the answer, but please explain how you get to it.....

Expert Solution

mass of carbon = 40.00 g

moles of C = 40 / 12 = 3.33

moles of H = 6.72 / 1 = 6.72

moles of O = 53.28 / 16 = 3.33

the ratios of all

C H O

3.33 6.72 3.33

1 2 1

Emperical formula = CH2O

mass of emperical formula = 12 + 2 + 16 = 30

molecular mass = 180.18 g/mol

n = 180 / 30 = 6

Molecular formula = 6 x CH2O

Molecular formula = C6H12O6

queen_honey_blossom answered 2 years ago

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