Luminol has a molecular weight of 177 g/mol. The forensic technician at a crime scene has...

Luminol has a molecular weight of 177 g/mol. The forensic technician at a crime scene has just prepared a luminol stock solution by adding 14.0 g of luminol into a total volume of 75.0 mL of H2O. Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2 M . The diluted solution is then placed in a spray bottle for application on the desired surfaces. What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?

Solutions

Expert Solution

MW = 177 g/mol

m = 14 g of luminol, Vtotal = 75 mL

C final = 6*10^-2 M

initial concentration:

mol = mass/MW = 14/177 = 0.079096 mol

M = mol/V = 0.079096/(75*10^-3) = 1.0546M

now

M1*V1 = M2*V2

V2 = M1/M2*V1 = 1.0546/(6*10^-2)*75

V2 = 1318.25 mL = 1.32 L required

queen_honey_blossom answered 2 years ago

Next > < Previous

Related Solutions

The forensic technician at a crime scene has just prepared a luminol stock solution by adding...

The forensic technician at a crime scene has just prepared a luminol stock solution by adding 10.0 g of luminol into a total volume of 75.0 mL of H2O. a ) What is the molarity of the stock solution of luminal? molarity of luminol solution = 0.753 M b) Before investigating the scene, the technician must dilute the luminol solution to a concentration of 4.00×10?2 M . The diluted solution is then placed in a spray bottle for application on...

Part A) The forensic technician at a crime scene has just prepared a luminol stock solution...

Part A) The forensic technician at a crime scene has just prepared a luminol stock solution by adding 15.0 g of luminol into a total volume of 75.0 mL of H2O. What is the molarity of the stock solution of luminol? Part B) Before investigating the scene, the technician must dilute the luminol solution to a concentration of 5.00×10−2 M . The diluted solution is then placed in a spray bottle for application on the desired surfaces. How many moles...

The forensic technician at a crime scene has just prepared a luminol stock solution by adding 16.0 g of luminol into a total volume of 75.0 mL of H2O.

Part A The forensic technician at a crime scene has just prepared a luminol stock solution by adding 16.0 g of luminol into a total volume of 75.0 mL of H2O. What is the molarity of the stock solution of luminol? Part B Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00x10-2 M. The diluted solution is then placed in a spray bottle for application on the desired surfaces. How many moles of luminol are present in 2.00...

Part A The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0 g of luminol into a total volume of 75.0 mL of H2O

Part A The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0 g of luminol into a total volume of 75.0 mL of H2O . What is the molarity of the stock solution of luminol? Express your answer with the appropriate units. molarity of luminol solution = 1.43 MPart B Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10?2 M . The diluted solution is then...

Acetic acid (molecular weight = 60.05 g/mol) and sodium acetate (molecular weight = 82.03 g/mol) can...

Acetic acid (molecular weight = 60.05 g/mol) and sodium acetate (molecular weight = 82.03 g/mol) can form a buffer with an acidic pH. In a 500.0 mL volumetric flask, the following components were added together and mixed well, and then diluted to the 500.0 mL mark: 100.0 mL of 0.300 M acetic acid, 1.00 g of sodium acetate, and 0.16 g of solid NaOH (molecular weight = 40.00 g/mol). What is the final pH? The Ka value for acetic acid...

1. a. A nylon 6,6 has an average molecular weight of 12078 g/mol. Calculate the average...

1. a. A nylon 6,6 has an average molecular weight of 12078 g/mol. Calculate the average degree of polymerization to 1 decimal of accuracy assuming the Nylon 6-6 mer is C12H22O2N2. b. Write a general chemical reaction for the chain polymerization of ethylene monomer into the linear polymer polyethylene. c. In general how does the processing of thermoplastics into the desired shape differ from the processing of thermosetting plastics? d. How can the higher strength of polyvinyl chloride as compared...

2. Ortho-dichlorobenzene has a molecular weight of 147.00 g/mol, but its MS has a very small...

2. Ortho-dichlorobenzene has a molecular weight of 147.00 g/mol, but its MS has a very small relative abundance of the 147 peak. Instead, it has peaks at 146 (100% relative abundance), 148 (65%), and 150 (10.6%). The peak at 147 is about 6.6% as big as the 146 peak. What causes this distinctive molecular ion region for this compound? What peaks (note the plural) would you expect to see on the mass spectrum for the fragment (note the lack of...

The molecular weight of methylene blue is 320 g/mol. The concentration of the original sample was...

The molecular weight of methylene blue is 320 g/mol. The concentration of the original sample was 0.005 mg/ml in 10 ml. Determine the molarity (M) of your original sample and each dilution. Original: Dilution 1 (1:2 add 3mL of methylene blue + 3mL of water) : Dilution 2 (1:4 use 3mL of of 1:2 solution + 3mL of water) : Dilution 3 (1:8 use 3mL of 1:4 solution + 3 mL of water) : Dilution 4 (1:10 use 0.5 ml...

Cytochrome C has a relative molecular weight of 11,384 g/mol. Calculate the extinction coefficient of cytochrome...

Cytochrome C has a relative molecular weight of 11,384 g/mol. Calculate the extinction coefficient of cytochrome C at 405nm from 6.1 mg/mL. Absorbance = 3.045

Phenylephrine HCL has a molecular weight of 203.66 g/mol. How many formula units are in 10...

Phenylephrine HCL has a molecular weight of 203.66 g/mol. How many formula units are in 10 mg of phenylephrine HCL?

Subjects