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calculate the ph of a mixture of 0.26M acetic acid (pKa 4.76) and 0.23 M sodium...

calculate the ph of a mixture of 0.26M acetic acid (pKa 4.76) and 0.23 M sodium acetate.

Solutions

Expert Solution

CH3COONa(aq) -----------------------> CH3COO^- (aq) + Na^+(aq)

0.23 M                                                 0.23M

PKa   = 4.76

-logKa   = 4.76

      Ka    = 10^-4.76   = 1.74*10^-5

      Kb   = Kw/Ka

               = 1*10^-14/1.74*10^-5   = 5.75*10^-10

         CH3COO^- + H2O -----------------> CH3COOH + OH^-

I         0.23                                                  0                  0

C      -x                                                        +x                +x

E     0.23-x                                                 +x                  +x

              Kb   = [CH3COOH][OH^-]/[CH3COO^-]

            5.75*10^-10    = x*x/(0.23-x)

           5.75*10^-10 *(0.23-x) = x^2

             x   = 1.15*10^-5

         [OH-]   = x   = 1.15*10^-5M

          POH   = -log[OH-]

                      = -log1.15*10^-5

                        = 4.9393

           PH      = 14-POH

                      = 14-4.9393   = 9.0607

             


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