Question

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calculate the ph of a mixture of 0.26M acetic acid (pKa 4.76) and 0.23 M sodium...

calculate the ph of a mixture of 0.26M acetic acid (pKa 4.76) and 0.23 M sodium acetate.

Expert Solution

CH3COONa(aq) -----------------------> CH3COO^- (aq) + Na^+(aq)

0.23 M 0.23M

PKa = 4.76

-logKa = 4.76

Ka = 10^-4.76 = 1.74*10^-5

Kb = Kw/Ka

= 1*10^-14/1.74*10^-5 = 5.75*10^-10

CH3COO^- + H2O -----------------> CH3COOH + OH^-

I 0.23 0 0

C -x +x +x

E 0.23-x +x +x

Kb = [CH3COOH][OH^-]/[CH3COO^-]

5.75*10^-10 = x*x/(0.23-x)

5.75*10^-10 *(0.23-x) = x^2

x = 1.15*10^-5

[OH-] = x = 1.15*10^-5M

POH = -log[OH-]

= -log1.15*10^-5

= 4.9393

PH = 14-POH

= 14-4.9393 = 9.0607

queen_honey_blossom answered 2 years ago

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