Question

In: Chemistry

A solution contains 1.5M sodium acetate. The pKa of acetic acid (a weak acid) is 4.76....

A solution contains 1.5M sodium acetate. The pKa of acetic acid (a weak acid) is 4.76. Calculate the fraction and percentage of the molecules existing in the unionized state.

Solutions

Expert Solution

CH3COO-    + H2O   -------------->   CH3COOH   + OH-

1.5                                                         0                   0

1.5 - x                                                    x                    x

Ka = x^2 / 1.5 - x

1.74 x 10^-5 = x^2 / 1.5 - x

x = 5.1x 10^-3

[OH-] = 5.1 x 10^-3 M

% un ionized = (5.1 x 10^-3 / 1.5 ) x 100

                   = 0.34 %


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