Question

In: Statistics and Probability

The score of a course out of 100 in Winter of 10 students are 48, 92,...

The score of a course out of 100 in Winter of 10 students are 48, 92, 47, 44, 94, 18, 95, 67, 74, 64

a. Calculate Q1, Q3 and IQR of the data.

b. Find the mean, median and standard deviation

c. Determine whether the smallest value of this data set is an outlier.

d. Comment the shape of the distribution.

Solutions

Expert Solution

Solution-

a)

b)

c) from data boxplot is constructed there is no outlier in the data

d) histogram

by histogram we can say shape of data is bimodal


Related Solutions

A study of 35 golfers showed that their average score on a particular course was 92....
A study of 35 golfers showed that their average score on a particular course was 92. The standard deviation of the population is 5. a. Find the best point estimate of the mean b. What is the margin of Error? c. Find the 95% confidence interval of the mean score for all golfers. d. Find the minimum number of golfers for 99 percent confidence when the score when the margin of error is 3.
A study of 35 golfers showed that their average score on a particular course was 92....
A study of 35 golfers showed that their average score on a particular course was 92. The standard deviation of the sample is 5. a. Find the best point estimate of the mean. b. Find the 95% confidence interval of the mean score for all golfers. c. Find the 99% confidence interval of the mean score for all golfers.
Assume that a student’s score in a course follows normal distribution. A sample of 10 students’...
Assume that a student’s score in a course follows normal distribution. A sample of 10 students’ scores is as follow: 65, 32, 78, 90, 45, 66, 78, 55, 24, 87. (a) Find the sample mean and sample standard deviation for this sample. (b) Find a 90% confidence interval for the mean score of all the students. Interpret the result. (c) Test, at significance level 10%, if the average score is lower than 70.
Consider the relationship between students’ score on a first course exam and their score on the...
Consider the relationship between students’ score on a first course exam and their score on the final exam. First-test score               Final-exam score 153                              145 144                              140 162                              145 149                              170 127                              145 118                              175 158                              170 153                              160 Using (1) your calculator, a pencil and graph paper and then (2) Excel: Plot the data with the first-test score on the x axis and the final-exam score on the y axis. Find the arithmetic mean, the mean absolute deviation and...
A. Out of 100 people sampled, 92 had kids. Based on this, construct a 95% confidence...
A. Out of 100 people sampled, 92 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. As in the reading, in your calculations: --Use z = 1.645 for a 90% confidence interval --Use z = 2 for a 95% confidence interval --Use z = 2.576 for a 99% confidence interval. Give your answers to three decimals Give your answers as decimals, to three decimal places. B. CNNBC recently reported that...
A makeup test is given and the average (μX) score out of 100 was 85.0, with...
A makeup test is given and the average (μX) score out of 100 was 85.0, with a SD (σX) of 3.0. Assuming a normal distribution, find the dividing line (test scores) between the A's, B's, C's, D's, and E's. This time the highest 6% will be the A's, the next 16% B's, the next 26% C's, the next 36% D's.
A test is given and the average (μX) score out of 100 was only a 53.1,...
A test is given and the average (μX) score out of 100 was only a 53.1, with a SD (σX) of 8.9. Assuming the grades followed a normal distribution, use the Z table or Excel and formulas to find the dividing line (test scores) between the A's, B's, C's, D's, and E's. Starting from the top, the teacher will give the highest 15% A's, the next 10% B's, the next 30% C's, the next 25% D's, and the bottom 20%...
A makeup test is given and the average (μX) score out of 100 was 85.0, with...
A makeup test is given and the average (μX) score out of 100 was 85.0, with a SD (σX) of 3.0. Assuming a normal distribution, find the dividing line (test scores) between the A's, B's, C's, D's, and E's. This time the highest 6% will be the A's, the next 16% B's, the next 26% C's, the next 36% D's.
A test is given and the average (μX) score out of 100 was only a 53.1,...
A test is given and the average (μX) score out of 100 was only a 53.1, with a SD (σX) of 8.9. Assuming the grades followed a normal distribution, use the Z table or Excel and formulas to find the dividing line (test scores) between the A's, B's, C's, D's, and E's. Starting from the top, the teacher will give the highest 15% A's, the next 10% B's, the next 30% C's, the next 25% D's, and the bottom 20%...
An SAT prep course claims to improve the test score of students. The table below shows...
An SAT prep course claims to improve the test score of students. The table below shows the scores for seven students the first two times they took the verbal SAT. Before taking the SAT for the second time, each student took a course to try to improve his or her verbal SAT scores. Do these results support the claim that the SAT prep course improves the students' verbal SAT scores? Let d=(verbal SAT scores prior to taking the prep course)−(verbal...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT