In: Statistics and Probability
A. Out of 100 people sampled, 92 had kids. Based on this,
construct a 95% confidence interval for the true population
proportion of people with kids.
As in the reading, in your calculations:
--Use z = 1.645 for a 90% confidence interval
--Use z = 2 for a 95% confidence interval
--Use z = 2.576 for a 99% confidence interval.
Give your answers to three decimals
Give your answers as decimals, to three decimal places.
B. CNNBC recently reported that the mean annual cost of auto
insurance is 994 dollars. Assume the standard deviation is 282
dollars. You take a simple random sample of 54 auto insurance
policies.
Find the probability that a single randomly selected value is less
than 969 dollars.
P(X < 969) =
Find the probability that a sample of size n=54n=54 is randomly
selected with a mean less than 969 dollars.
P(¯xx¯ < 969) =
C. Out of 400 people sampled, 332 preferred Candidate A. Based
on this, estimate what proportion of the voting population (pp)
prefers Candidate A.
Use a 95% confidence level, and give your answers as decimals, to
three places.
(A)
n = 100
p = 0.92
% = 95
Standard Error, SE = √{p(1 - p)/n} = √(0.92(1 - 0.92))/100 = 0.02712932
z- score = 1.959963985
Width of the confidence interval = z * SE = 1.95996398454005 * 0.0271293199325011 = 0.05317249
Lower Limit of the confidence interval = P - width = 0.92 - 0.0531724899927667 = 0.86682751
Upper Limit of the confidence interval = P + width = 0.92 + 0.0531724899927667 = 0.97317249
The 95% confidence interval is [0.867, 0.973]
(B)
(a) μ = 994, σ = 282, x = 969
z = (x - μ)/σ = (969 - 994)/282 = -0.0887
P(x < 969) = P(z < -0.0887) = 0.4647
(b) μ = 994, σ = 282, n = 54, x-bar = 969
z = (x-bar - μ)/(σ/√n) = (969 - 994)/(282/√54) = -0.6515
P(x-bar < 969) = P(z < -0.6515) = 0.2574
(C)
n = 400
p = 0.83
% = 95
Standard Error, SE = √{p(1 - p)/n} = √(0.83(1 - 0.83))/400 = 0.01878164
z- score = 1.959963985
Width of the confidence interval = z * SE = 1.95996398454005 * 0.018781639970993 = 0.03681134
Lower Limit of the confidence interval = P - width = 0.83 - 0.0368113379137441 = 0.79318866
Upper Limit of the confidence interval = P + width = 0.83 + 0.0368113379137441 = 0.86681134
The 95% confidence interval is [0.793, 0.869]