In: Statistics and Probability
Consider the relationship between students’ score on a first course exam and their score on the final exam.
First-test score Final-exam score
153 145
144 140
162 145
149 170
127 145
118 175
158 170
153 160
Using (1) your calculator, a pencil and graph paper and then (2) Excel:
please answer each of them clearly
a)
b)
first-test | final-exam | abs dev. First -test | abs dev final-exam | |
153 | 145 | 7.5 | 11.25 | |
144 | 140 | 1.5 | 16.25 | |
162 | 145 | 16.5 | 11.25 | |
149 | 170 | 3.5 | 13.75 | |
127 | 145 | 18.5 | 11.25 | |
118 | 175 | 27.5 | 18.75 | |
158 | 170 | 12.5 | 13.75 | |
153 | 160 | 7.5 | 3.75 | |
mean | 145.5 | 156.25 | 11.875 | 12.5 |
standard deviation | 15.3715879 | 14.0788595 | ||
r | -0.20133329 |
Formulas
first-test | final-exam | abs dev. First -test | abs dev final-exam | |
153 | 145 | =ABS(B2-145.5) | =ABS(C2-156.25) | |
144 | 140 | =ABS(B3-145.5) | =ABS(C3-156.25) | |
162 | 145 | =ABS(B4-145.5) | =ABS(C4-156.25) | |
149 | 170 | =ABS(B5-145.5) | =ABS(C5-156.25) | |
127 | 145 | =ABS(B6-145.5) | =ABS(C6-156.25) | |
118 | 175 | =ABS(B7-145.5) | =ABS(C7-156.25) | |
158 | 170 | =ABS(B8-145.5) | =ABS(C8-156.25) | |
153 | 160 | =ABS(B9-145.5) | =ABS(C9-156.25) | |
mean | =AVERAGE(B2:B9) | =AVERAGE(C2:C9) | =AVERAGE(D2:D9) | =AVERAGE(E2:E9) |
standard deviation | =STDEV(B2:B9) | =STDEV(C2:C9) | ||
r | =CORREL(B2:B9,C2:C9) |
for first -test
mean = 145.5
MAD = 11.875
sd = 15.37159
for final exam
mean =156.25
MAD= 12.5
sd = 14.0789
r = -0.2013
c)
since r < 0
there is negative correlation, value of r is less than 0.3, hence it is weak correlation