Question

In: Statistics and Probability

Consider the relationship between students’ score on a first course exam and their score on the...

Consider the relationship between students’ score on a first course exam and their score on the final exam.

First-test score               Final-exam score

153                              145

144                              140

162                              145

149                              170

127                              145

118                              175

158                              170

153                              160

Using (1) your calculator, a pencil and graph paper and then (2) Excel:

  1. Plot the data with the first-test score on the x axis and the final-exam score on the y axis.
  2. Find the arithmetic mean, the mean absolute deviation and the standard deviation for both variables. Find the correlation between the two variables
  3. Write a brief explanation of what you have found and how the statistics you calculated support your explanation.

please answer each of them clearly

Solutions

Expert Solution

a)

b)

first-test final-exam abs dev. First -test abs dev final-exam
153 145 7.5 11.25
144 140 1.5 16.25
162 145 16.5 11.25
149 170 3.5 13.75
127 145 18.5 11.25
118 175 27.5 18.75
158 170 12.5 13.75
153 160 7.5 3.75
mean 145.5 156.25 11.875 12.5
standard deviation 15.3715879 14.0788595
r -0.20133329

Formulas

first-test final-exam abs dev. First -test abs dev final-exam
153 145 =ABS(B2-145.5) =ABS(C2-156.25)
144 140 =ABS(B3-145.5) =ABS(C3-156.25)
162 145 =ABS(B4-145.5) =ABS(C4-156.25)
149 170 =ABS(B5-145.5) =ABS(C5-156.25)
127 145 =ABS(B6-145.5) =ABS(C6-156.25)
118 175 =ABS(B7-145.5) =ABS(C7-156.25)
158 170 =ABS(B8-145.5) =ABS(C8-156.25)
153 160 =ABS(B9-145.5) =ABS(C9-156.25)
mean =AVERAGE(B2:B9) =AVERAGE(C2:C9) =AVERAGE(D2:D9) =AVERAGE(E2:E9)
standard deviation =STDEV(B2:B9) =STDEV(C2:C9)
r =CORREL(B2:B9,C2:C9)

for first -test

mean = 145.5

MAD = 11.875

sd = 15.37159

for final exam

mean =156.25

MAD= 12.5

sd = 14.0789

r = -0.2013

c)

since r < 0

there is negative correlation, value of r is less than 0.3, hence it is weak correlation


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