In: Statistics and Probability
Let the mean birth weight of male babies population is
.
Standard deviation is ,
= 1.33
Let X be a random variable denoting birth weights of a male babies.
n =400 .
So,from central limit theorem we know that mean of it will follow normal since n is very large
So,
N(
,
2/n)
=N (
, 1.77/400)
Now, P (
-.125
+.125 ) = P ( (
-.125 -
)/(
/
)
(
-
)/(
/
)
(
+.125 -
)/(
/
))
=P(-.125/(1.33/20)
Z
.125/(1.33/20)) [converting to standard normal]
= P( -1.88
Z
1.88)
= P (Z
1.88) - P( Z
-1.88)
=
-
[
is distribution function for standard normal]
=
- (1 -
)
=2 x
- 1
=2 x 0.96995 -1
= 0.9399
Probability that the mean birth weight is within .125 lb of the population mean birth weights of all male babies is , 0.9399 or 93.99 % .
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