In: Statistics and Probability
Let the mean birth weight of male babies population is .
Standard deviation is , = 1.33
Let X be a random variable denoting birth weights of a male babies.
n =400 .
So,from central limit theorem we know that mean of it will follow normal since n is very large
So, N( ,2/n) =N ( , 1.77/400)
Now, P ( -.125 +.125 ) = P ( ( -.125 - )/(/) (- )/(/) ( +.125 - )/(/))
=P(-.125/(1.33/20) Z .125/(1.33/20)) [converting to standard normal]
= P( -1.88 Z 1.88)
= P (Z 1.88) - P( Z -1.88)
= - [ is distribution function for standard normal]
= - (1 - )
=2 x - 1
=2 x 0.96995 -1
= 0.9399
Probability that the mean birth weight is within .125 lb of the population mean birth weights of all male babies is , 0.9399 or 93.99 % .
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