Question
In: Statistics and Probability
The birth weights for two groups of babies were compared in a study. In one group...
The birth weights for two groups of babies were compared in a study. In one group the mothers took a zinc supplement during pregnancy. In another group, the mothers took a placebo. A sample of 129 babies in the zinc group had a mean birth weight of 3469 grams. A sample of 142 babies in the placebo group had a mean birth weight of 3318 grams. Assume that the population standard deviation for the zinc group is 843 grams, while the population standard deviation for the placebo group is 775 grams. Determine the 95% confidence interval for the true difference between the mean birth weights for "zinc" babies versus "placebo" babies.
Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval.
Solutions
orchestra answered 1 year agoRelated Solutions
The birth weights for two groups of babies were compared in a study. In one group...
The birth weights for two groups of babies were compared in a
study. In one group the mothers took a zinc supplement during
pregnancy. In another group, the mothers took a placebo. A sample
of 135 babies in the zinc group had a mean birth weight of 3075
grams. A sample of 141 babies in the placebo group had a mean birth
weight of 3002 grams. Assume that the population standard deviation
for the zinc group is 803 grams, while...
The birth weights for two groups of babies were compared in a study. In one group...
The birth weights for two groups of babies were compared in a
study. In one group the mothers took a zinc supplement during
pregnancy. In another group, the mothers took a placebo. A sample
of 138 babies in the zinc group had a mean birth weight of 3016
grams. A sample of 111 babies in the placebo group had a mean birth
weight of 3343 grams. Assume that the population standard deviation
for the zinc group is 790 grams, while...
The birth weights for two groups of babies were compared in a study. In one group...
The birth weights for two groups of babies were compared in a
study. In one group the mothers took a zinc supplement during
pregnancy. In another group, the mothers took a placebo. A sample
of 33 babies in the zinc group had a mean birth weight of 3249
grams. A sample of 31 babies in the placebo group had a mean birth
weight of 3143 grams. Assume that the population standard deviation
for the zinc group is 870 grams, while...
The birth weights for two groups of babies were compared in a study. In one group...
The birth weights for two groups of babies were compared in a
study. In one group the mothers took a zinc supplement during
pregnancy. In another group, the mothers took a placebo. A sample
of 227 babies in the zinc group had a mean birth weight of 3255
grams. A sample of 276 babies in the placebo group had a mean birth
weight of 30023002 grams. Assume that the population standard
deviation for the zinc group is 708 grams, while...
The birth weights for two groups of babies were compared in a study. In one group...
The birth weights for two groups of babies were compared in a
study. In one group the mothers took a zinc supplement during
pregnancy. In another group, the mothers took a placebo. A sample
of 98 babies in the zinc group had a mean birth weight of 3423
grams. A sample of 80 babies in the placebo group had a mean birth
weight of 3004 grams. Assume that the population standard deviation
for the zinc group is 686 grams, while...
In planning a study of birth weights of babies whose mothers did not see a doctor...
In planning a study of birth weights of babies whose mothers did
not see a doctor before delivery, a researcher states the
hypotheses as
LaTeX: H_0: \bar{x} = 1000 grams \\H_a: \bar{x}<1000 grams H
0 : x ¯ = 1000 g r a m s H a : x ¯ < 1000 g r a m s
What is wrong with the hypotheses as they are written?
Group of answer choices
Nothing is wrong with the hypotheses.
Hypotheses are about...
When birth weights were recorded for a simple random sample of 16 male babies born to...
When birth weights were recorded for a simple random sample of
16 male babies born to mothers taking a special vitamin supplement,
the sample had a mean of 3.675 kilograms and a standard deviation
of 0.657 kilogram. The birth weights for all babies are assumed to
normally distributed. Use a 0.05 significance level to test the
claim that the mean birth weight for all male babies of mothers
taking the vitamin supplement is different from 3.39 kilograms,
which is the...
12 subjects in a study were randomly assigned into two equally sized groups. One group was...
12 subjects in a study were randomly assigned into two
equally sized groups. One group was shown a short video on how to
fold paper cranes. The other group was given an instruction booklet
on how to do so. They were then asked to make paper cranes for the
next hour. The number of paper cranes each subject made was
recorded and is listed in the table below. The researchers are
interested in whether there was a difference in the...
A prenatal intervention to increase birth weights of babies was being studied. Dataset A is the...
A prenatal intervention to increase birth weights of babies was
being studied. Dataset A is the sample of birth weights for babies
whose mothers participated in the program, while dataset B is for
babies whose mothers did not participate.
A: 6.1, 5.5, 5.6, 7.0, 6.9, 7.4, 8.0, 9.0, 7.8, 6.9, 8.2, 7.4,
8.3, 6.8, 7.4
B: 6.0, 6.1, 5.5, 5.8, 5.3, 5.9, 5.9, 6.3, 5.7, 6.6, 7.0, 4.5,
5.5, 5.2
1- Obtain a 95% confidence interval for the
difference between...
The birth weights of full term babies born in Sydney are normally distributed. The management of...
The birth weights of full term babies born in Sydney are
normally distributed. The management of a Sydney hospital is
considering the resources needed to care for low birth-weight
babies, and to this end, an analyst is doing some preliminary
research on the distribution of birth-weights.
a. The analyst obtained a random sample of the weights of 51
full term babies recently born in Sydney. The sample mean was 2.98
kg and the sample standard deviation was 0.39 kg. Calculate...
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