Question

In: Chemistry

Part A What mass of calcium can be produced by this process if a current of...

Part A What mass of calcium can be produced by this process if a current of 6300 A is applied for 39 h ? Assume that the electrolytic cell is 65 % efficient. Part A What mass of calcium can be produced by this process if a current of 6300 A is applied for 39 h ? Assume that the electrolytic cell is 65 % efficient. Part B What is the minimum voltage needed to cause the electrolysis?

Part B

How many minutes are needed to plate out 22.00 g Mg from molten MgCl2, using 3.00 A of current?

Expert Solution

part-A Ca⁺² + 2e^- -------> Ca

Z= 2

W = MCt/ZF

= 40*6300*6*60*60/2*96500 = 28203.1g

part-B W = MCt/ZF

Mg⁺² + 2e^- --------> Mg

Z = 2

W = 22

M = 24

F = 96500c

C= 3A

W = MCt/ZF

t = WZF/MC

= 22*2*96500/24*3 = 58972.2sec = 58972.2/60 = 982.87min

queen_honey_blossom answered 1 year ago

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