Question

14. A researcher reports outcomes of one-factor ANOVA as F(5, 60) = 3.24, p > .05. Based on the df values, how many groups were compared in the study, and what was the total number of subjects participating in the study?

• A. 6 groups & total of 66 participants.

• B. 4 groups & total of 64 participants.

• C. 5 groups & total of 55 participants.

• D. 4 groups & total of 60 participants.

16. A one-way ANOVA is used to evaluate the mean differences in BMI (i.e., body mass index) between three groups of adults - young adults, middle age adults and elderly. Each age group had n = 10 participants. If the data produced an F-ratio of F = 3.38, which of the following is the correct conclusion from this study (assume p <. 05)?

• A. Reject the null hypothesis and conclude that there are no significant differences in mean BMI.

• B. Fail to reject the null hypothesis and conclude that there are significant differences in mean BMI.

• C. Reject the null hypothesis and conclude that there were significant differences in mean BMI.

• D. Fail to reject the null hypothesis and conclude that there are no significant differences in mean BMI.

17.A one-way ANOVA is used to evaluate the mean differences between five experimental
groups, with n = 12 participants in each group. If the data produce an F= 4.74, which of the following is the correct statistical decision?

• A. Reject the null hypothesis with α = .05 but fail to reject with α = .01.

• B. Reject the null hypothesis with either α = .05 or α = .01.

• C. Fail to reject the null hypothesis with either α = .05 or α = .01.

• D. Reject the null hypothesis with α = .01 but fail to reject with α = .05.

19.

A researcher wanted to examine if the type of music one listens to while studying affects memory performance. She randomly selected five samples of participants and assigned each of them to one of five experimental conditions - listening to classical music, jazz, R&R, R&B or Hip hop. Each sample had 14 subjects (n = 14). All participants were asked to memorize a list of words while listening to one of the five types of music tested. At the end, all participants took a memory test. One-factor ANOVA for independent samples was conducted to test if there is a significant effect of music type on memory performance. The results of the analysis are shown in the following ANOVA summary table.

                          

                                           Source       SS         df        MS             

                           Between Treatments     48       ____     ____    F = 3.00  

                           Within Treatments      ____     ____     ____    

                           Total                        ____     ____

          A. Fill in all missing values in the ANOVA summary table. Show your work (i.e., all computational steps for finding the missing values). Hint: start with the df values and figure out the rest by solving simple equations with one unknown (i.e., refer to the computational formulas for df, MS & F statistic).

       

           B. Do the data indicate a significant effect of type music on memory performance (assume p < .05)? Use the outcomes of one-factor ANOVA summarized in the table to test this research question.

• the null hypothesis H₀ & the alternative hypothesis H₁ ?
• the critical F used for the decision about H₀ ?
• the decision about H₀?
• if the difference is statistically significant, the effect size, η²?

Answer 1

Solution-14

k=5

k=5+1=6

Total=5+60+1=66

A. 6 groups & total of 66 participants.

Solution-16

16. A one-way ANOVA is used to evaluate the mean differences in BMI (i.e., body mass index) between three groups of adults - young adults, middle age adults and elderly. Each age group had n = 10 participants. If the data produced an F-ratio of F = 3.38, which of the following is the correct conclusion from this study (assume p <. 05)?

Ho:mu1=mu2=mu3

Ha:atleast one of the group means are different

p<0.05

Reject Ho

Accept Ha

Atleast one of the group means are different

C. Reject the null hypothesis and conclude that there were significant differences in mean BMI

Solution-17:

k=5

df (numerator)=k-1=5-1=4

df(denominator)=n-k=60-5=55

p value in excel

==F.DIST.RT(4.74,4,55)

=0.002335296

p=0.0023

p<0.05

also P<0.01

Reject Ho

B. Reject the null hypothesis with either α = .05 or α = .01