Question

Practice Exercise 14: One -way Analysis of Variance (ANOVA) Use the One-way ANOVA function in SPSS to answer the questions based on the following scenario. Select Descriptives from the Options menu to obtain the means and standard deviations. (Assume a critical level of significance of .05). Researchers are interested in determining if the type of medication influences the number of days it takes for symptoms to cease. Thirty-six patients are randomly assigned to receive Brand X, Brand Y, or Brand Z medication. The number of days before symptoms ceased are reported below. Brand X: 20 30 26 15 13 24 28 19 23 29 17 25 Brand Y: 15 5 23 15 22 23 18 24 19 16 10 6 Brand Z: 14 15 16 20 21 24 14 23 17 11 14 22 1. Write an appropriate null hypothesis for this analysis. 8. Based on the reported level of significance, would you reject the null hypothesis? 9. Based on the reported level of significance, would you conclude that there was a statistically significant difference among the three groups? 10. Write a statement as it might appear in an article that reports the results of the one-way ANOVA. PLEASE COULD U HELP ME BECAUSE THE DUE DATE IS TODAY!!!!

Answer 1

Groups	Count	Sum	Average	Variance
Brand X	12	269	22.41667	31.35606
Brand Y	12	196	16.33333	42.60606
Brand Z	12	211	17.58333	18.08333

One way ANOVA:

The test statistic:

k= no of variables=3

N= number of observations= 36

n= number of observations per each variable

P-value: 0.027017

F-critical: 3.284918

The test statistic p-value is less than 0.05 significant level.

The test statistic is significant and rejects H0. There is sufficient evidence to conclude that there was a statistically significant difference among the three groups.