In: Statistics and Probability
The number of cars sold annually by used car salespeople is normally distributed with a standard deviation of σ = 15. A random sample of 36 salespeople was taken and the mean number of cars sold annually was found to be 141. Find the 99% confidence interval estimate of the population mean.
Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits.
(a) [3 pts] What process of finding confidence interval you would choose and why?
(b) [4 pts] Find the margin of error:
(c) [4 pts] Find the confidence interval:
(d) [4 pts] Interpret the confidence Interval:
Solution :
Given that,
a)Single-Sample Confidence Interval Using the Z Statistic, because is known .
Point estimate = sample mean =
= 141
Population standard deviation =
= 15
Sample size = n = 36
At 99% confidence level
= 1-0.99% =1-0.99 =0.01
/2
=0.01/ 2= 0.005
Z/2
= Z0.005 = 2.576
Z/2 = 2.576
b) Margin of error = E = Z/2
* (
/n)
= 2.576 * ( 15 / 36 )
= 6.44
c) At 99 % confidence interval estimate of the population mean
is,
- E <
<
+ E
141 - 6.44 <
< 141+ 6.44
134.56 <
< 147.44
(134.56 , 147.44)
Lower confidence interval =134.56
Upper confidence interval=147.44
D) The 99% confidence interval estimate of the population mean is =(134.56 , 147.44)