In: Statistics and Probability
The number of cars sold annually by used car salespeople is normally distributed with a standard deviation of 14. A random sample of 300 salespeople was taken and the mean number of cars sold annually was found to be 69. Find the 92% confidence interval estimate of the population mean.
Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits.
Confidence Interval =
Solution :
Given that,
Point estimate = sample mean =  
   =69
Population standard deviation =   
= 14
Sample size n = 300
At 92% confidence level the z is ,
= 1 - 92% = 1 - 0.92 = 0.08
/ 2 =0.04
Z
/2
= Z0.04= 1.75 ( Using z table )
Margin of error = E =   Z
/2   
* ( 
 /n)
= 1.75* (14 /   300)
= 1.4145
At 92% confidence interval estimate of the population mean
is,
- E < 
 < 
 + E
69- 1.4145<  
< 69 + 1.4145
67.5855<  
<70.4145
(  LCL =67.5855 ,UCL =70.4145 )