In: Statistics and Probability
The number X of cars that Linda hopes to sell has the distribution:
Cars sold 0 1 2 3
Probability 0.2 0.1 0.3 0.4
Find the mean and standard deviation of X.
|
1.9, 1.29 |
||
|
0.25, 1.29 |
||
|
1.9, 1.136 |
||
|
0.25, 1.136 |
Solution:
| x | P(x) | x * P(x) | x2 * P(x) |
| 0 | 0.2 | 0 | 0 |
| 1 | 0.1 | 0.1 | 0.1 |
| 2 | 0.3 | 0.6 | 1.2 |
| 3 | 0.4 | 1.2 | 3.6 |
| Sum | 1 | 1.9 | 4.9 |
Mean =
X * P(X)
= 1.9
Standard deviation =
=
X
2 * P(X) -
2
=
4.9
- (1.9)2 = 1.29
Standard deviation =
= 1.136
The mean and Standard deviation of X . 1.9 , 1.136