In: Physics
A metal block of mass 1.830 kg is hanging from a string. The tension in the string is 1.089×101 N. The block is submerged in a beaker of fluid and is stationary. What is the magnitude and direction of the buoyant force acting on the block?
Mass of the block m = 1.830 kg
Weight of the block W = mg
= 1.830 kg x 9.8 m/s 2
= 17.934 N
Tension in the string T = 1.089 x10 1 N
= 10.89 N
The magnitude of the buoyant force acting on the block F = W-T
= 7.044 N
Direction : along upward direction.i.e., opposite to weight direction