A metal block of mass 1.830 kg is hanging from a string. The tension in the...

A metal block of mass 1.830 kg is hanging from a string. The tension in the string is 1.089×10¹ N. The block is submerged in a beaker of fluid and is stationary. What is the magnitude and direction of the buoyant force acting on the block?

Solutions

Expert Solution

Mass of the block m = 1.830 kg

Weight of the block W = mg

= 1.830 kg x 9.8 m/s ²

= 17.934 N

Tension in the string T = 1.089 x10 ¹ N

= 10.89 N

The magnitude of the buoyant force acting on the block F = W-T

= 7.044 N

Direction : along upward direction.i.e., opposite to weight direction

genius_generous answered 1 year ago

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