Question

In: Physics

Part a A string has a mass density of 5.00x10-4 kg/m and it's under a tension...

Part a

A string has a mass density of 5.00x10-4 kg/m and it's under a tension of 5N. The string is .8m between both ends, calculate the first four harmonic frequencies.

Part b

A metal rod has a density of 3000 kg/m3 and a bulk modulus of 60Gpa. The rod is 1 meter long, calculate the frequencies for the first two harmonics.

Expert Solution

fundamental frequency f = 1/2l T/

f₁= 1/1610⁴

first harmonic f₁= 100/16 =6.25Hz

second " f₂=2f₁=12.5Hz

third " f₃=3f₁= 18.75Hz

fourth " f₄= 4f₁= 25Hz

b> frequency of rod f = Y/

first harmonic f₁=20*10⁶

f₁=4.48*10³Hz

second harmonic f₂ = 8.96*10^3Hz

genius_generous answered 8 months ago

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