Question

In: Physics

Part a A string has a mass density of 5.00x10-4 kg/m and it's under a tension...

Part a
A string has a mass density of 5.00x10-4 kg/m and it's under a tension of 5N. The string is .8m between both ends, calculate the first four harmonic frequencies.

Part b
A metal rod has a density of 3000 kg/m3 and a bulk modulus of 60Gpa. The rod is 1 meter long, calculate the frequencies for the first two harmonics.

Solutions

Expert Solution

fundamental frequency f = 1/2l T/

                                 f1= 1/16104

            first harmonic f1= 100/16 =6.25Hz

            second "      f2=2f1=12.5Hz

            third    "        f3=3f1= 18.75Hz

            fourth   "       f4= 4f1= 25Hz

b>       frequency of rod f = Y/

                   first harmonic f1=20*106

                                        f1=4.48*103Hz

                   second harmonic f2 = 8.96*103Hz


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