Question
In: Statistics and Probability
Now, let’s calculate the least-squares line based on your data. Show your work. x y x2...
- Now, let’s calculate the least-squares line based on your data. Show your work.
|
x |
y |
x2 |
xy |
y2 |
|
1045 |
183 |
|||
|
2266 |
283 |
|||
|
584 |
163 |
|||
|
444 |
205 |
|||
|
2746 |
283 |
|||
|
698 |
146 |
|||
|
796 |
143 |
|||
|
1304 |
223 |
|||
2. Determine the Sample Correlation Coefficient, .
Solutions
Expert Solution
Solution :
| X | Y | XY | X^2 | Y^2 |
| 1045 | 183 | 191235 | 1092025 | 33489 |
| 2266 | 283 | 641278 | 5134756 | 80089 |
| 584 | 163 | 95192 | 341056 | 26569 |
| 444 | 205 | 91020 | 197136 | 42025 |
| 2746 | 283 | 777118 | 7540516 | 80089 |
| 698 | 146 | 101908 | 487204 | 21316 |
| 796 | 143 | 113828 | 633616 | 20449 |
| 1304 | 223 | 290792 | 1700416 | 49729 |
| n | 8 |
| sum(XY) | 2302371.00 |
| sum(X) | 9883.00 |
| sum(Y) | 1629.00 |
| sum(X^2) | 17126725.00 |
| sum(Y^2) | 353755.00 |
| Numerator | 2319561.00 |
| Denominator | 2634303.75 |
| r | 0.8805 |
| r square | 0.7753 |
| Xbar(mean) | 1235.3750 |
| Ybar(mean) | 203.6250 |
| SD(X) | 884.7641 |
| SD(Y) | 54.3377 |
| b | 0.0590 |
| a | 130.7852 |
Sample Correlation Coefficient = r = 0.8805
orchestra answered 2 years agoRelated Solutions
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