Question

In: Statistics and Probability

An article gave a scatter plot along with the least squares line of x = rainfall...

An article gave a scatter plot along with the least squares line of x = rainfall volume (m3) and y = runoff volume (m3) for a particular location. The accompanying values were read from the plot.

x 8 12 14 18 23 30 40 47 55 67 72 82 96 112 127
y 4 10 13 14 15 25 27 48 38 46 53 75 82 99 101

(a) Does a scatter plot of the data support the use of the simple linear regression model?

Yes, the scatterplot shows a reasonable linear relationship. Yes, the scatterplot shows a random scattering with no pattern.     No, the scatterplot shows a reasonable linear relationship. No, the scatterplot shows a random scattering with no pattern.


(b) Calculate point estimates of the slope and intercept of the population regression line. (Round your answers to five decimal places.)

slope     
intercept     


(c) Calculate a point estimate of the true average runoff volume when rainfall volume is 52. (Round your answer to four decimal places.)
m3

(d) Calculate a point estimate of the standard deviation σ. (Round your answer to two decimal places.)
m3

(e) What proportion of the observed variation in runoff volume can be attributed to the simple linear regression relationship between runoff and rainfall? (Round your answer to four decimal places.)

Solutions

Expert Solution

a)

Yes, the scatterplot shows a reasonable linear relationship

b)

slope =0.84503

intercept =-1.90368

c)

predicted val=-1.90368+52*0.84503= 42.0379 (please try 42.0376 if this comes wrong)

d)

SST =                   'Σ(Yi-Y̅)2                 = 14917.333
SSR =                   'Σ(Ŷ-Y̅)2                 = 14488.237
SSE =                   'Σ(Yi-Ŷ)2                 = 429.0968
s2 =SSE/(n-2)= 33.0074
std error σ              = =se =√s2= 5.75

e)

Coeffficient of determination R^2 =SSR/SST= 0.9712

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