In: Chemistry
What would be the effect on the percent Pb reported in the analysis if:
a. the precipitate of PbCrO4 was not completely dried?
b. some of the unknown lead salt was spilled while transferring the sample to the beaker?
c. the orange precipitate of PbCrO4 was not completely transferred to the filter paper?
(a) If the given precipitate is not fully dry then when we measure the mass, we will get a higher mass of PbCrO4 (s) than the actual yield as currently we are measuring the mass of PbCrO4 (s) plus the water. A higher mass of PbCrO4 (s) will result in calculating higher number of moles of PbCrO4 (s), which will be then converted into higher moles in the mixture. In the last we end up calculating that the mass percent of Pb(s) is higher than it actual is.
(b) When the unknown lead salt was spilled while transferring to the beaker, then there was found less amount of PbCrO4 and it gives less amount of moles and concentration, so PbCrO4 also got the lesser in number and molarity got low.
(c) the orange precipitate of PbCrO4 was not completely transferred to the filter paper then mass percent of Pb will not have any effect only the overall yield will be less since the reaction has been completed and only the weight is found to be less