Question

In: Advanced Math

List examples of equations similar to the Pell's equation, ie. any  Diophantine equation other then Pell's.

List examples of equations similar to the Pell's equation, ie. any  Diophantine equation other then Pell's.

Solutions

Expert Solution

a)

Linear Combination

A Diophantine equation in the form is known as a linear combination. If two relatively prime integers and are written in this form with , the equation will have an infinite number of solutions. More generally, there will always be an infinite number of solutions when . If , then there are no solutions to the equation. To see why, consider the equation . is a divisor of the LHS (also notice that must always be an integer). However, will never be a multiple of , hence, no solutions exist.

Now consider the case where . Thus, . If and are relatively prime, then all solutions are obviously in the form for all integers . If they are not, we simply divide them by their greatest common divisor.

Pythagorean Triples

Main article: Pythagorean triple

A Pythagorean triple is a set of three integers that satisfy the Pythagorean Theorem, . There are three main methods of finding Pythagorean triples:

Method of Pythagoras

If is an odd number, then is a Pythagorean triple.

Method of Plato

If , is a Pythagorean triple.

Babylonian Method

For any , is a Pythagorean triple.

Sum of Fourth Powers

A equation of form has no integer solutions, as follows: We assume that the equation does have integer solutions, and consider the solution which minimizes . Let this solution be . If then their GCD must satsify . The solution would then be a solution less than , which contradicts our assumption. Thus, this equation has no integer solutions.

If , we then proceed with casework, in .

Note that every square, and therefore every fourth power, is either or . The proof of this is fairly simple, and you can show it yourself.


Case 1:

This would imply , a contradiction.


Case 2:

This would imply , a contradiction since we assumed .


Case 3: , and

We also know that squares are either or . Thus, all fourth powers are either or .


By similar approach, we show that:


, so .

This is a contradiction, as implies is odd, and implies is even. QED


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