Question

If there is appeoximately 84,000 people living in Nampa, Idaho and there is an average of 4 people per household and that each household owns 2 cars, how much total carbon dioxide is generated (@ STP) by the residents of the city of Nmmpa each year with the following information:

(A) Each car has a 16 gallon gasoline tank

(B) Each car in each household consumes one tank ofgasoline per week (52 weeks per year)

(C) Assume that gasoline is pure benzene (C6H6) and is burned to completion in air when the tank is emptied

Q: Approx. hoow much total Liiters of CARBON DIOXIDE GAS is generated by the residents of Nampa, Idaho only driving their cars and consuming one tankful per week of gasoline in each car for each of the 52 weeks in the year?

Answer 1

total people = 84000

4 people per household = 84000/4 = 21000 household

each household owns 2 car = 21000 2 = 42000 car

1 gallon = 3.78541 liter

then 16 gallon = 16 3.78541 = 60.56656 L

Each car use 60.56656 Liter gasoline per week

52 week in year then 60.56656 52 = 3149.46112 Liter

Each car use 3149.46112 liter gasoline per year

then 42000 car uses = 3149.46112 42000 = 132277367.04 Liter

Total gasoline use = 132277367.04 Liter

density of gasoline = 876.5 gm/liter

mass = volume density

total mass of gasoline = 132277367.04 876.5 = 115941112211 gm

molar mass of benzene = 78.11 gm/mole

that mean 1 mole of benzene = 78.11 gm then 115941112211 gm benzene = 115941112211 /78.11 = 1484331227.9 mole of benzene

combution reaction of benzene

2C₆H₆  + 15O₂ 12CO₂ + 6H₂O

According to reaction 2 mole of benzene produce 12 mole of carbon dioxide then 1484331227.9 of benzene produce

1484331227.9 12 / 2 = 8905987367.5 mole of carbon dioxide

accrding to avogadro's law at STP 1 mole of gas occupy volume 22.414 liter then 8905987367.5 mole of carbon dioxide occupy volume = 8905987367.5 22.414 = 199618800855 Liter

199618800855 Liter of carbon dioxide genrated.