Question

Part A

Calculate the number of C atoms in 0.602 mole of C.

Part B

Calculate the number of SO2 molecules in 6.82 moles of SO2.

Part C

Calculate the moles of Fe in 2.34x1022 atoms of Fe.

Part D

Calculate the moles of C2H6O in 3.97x1024 molecules of C2H6O.

Answer 1

Part A:

1 mole of C contains 6.023*10^23 C atoms so

0.602 mole of C will contain

= 0.602 mole of C *( 6.023*10^23 C atoms / 1 mole of C)

= 3.63 *10^23 C atoms

Therefore, the number of C atoms in 0.602 mol of C are 3.63 *10^23

Part B:

1 mole of SO2 = 6.023*10^23 molecules so

6.82 mole of SO2 =

= 6.82 mole of SO2 *(6.023*10^23 molecules / 1 mole of SO2)

= 4.11*10^22 molecules of SO2

Therefore, the number of molecules of SO2 in 6.82 mole of SO2 = 4.11*10^22

Part C:

6.023*10^23 atoms of Fe = 1 mole so

2.34*10^22 atoms of Fe =

= 2.34*10^22 atoms of Fe *(1 mole / 6.023*10^23 atoms of Fe)

= 0.389 *10^-1 mole = 0.0389 mole

Therefore, the number of moles of Fe = 0.0389

Part D:

6.023*10^23 molecules of C2H6O = 1 mole so

3.97*10^24 molecules of C2H6O =

= 3.97*10^24 molecules *(1 mole / 6.023*10^23 molecules)

= 6.59 mole

Therefore, the number of moles of C2H6O present in 3.97*10^24 molecules are 6.59