In: Statistics and Probability
A study was conducted on students from a particular high school
over the last 8 years. The following information was found
regarding standardized tests used for college admitance. Scores on
the SAT test are normally distributed with a mean of 992 and a
standard deviation of 201. Scores on the ACT test are normally
distributed with a mean of 19.1 and a standard deviation of 5.1. It
is assumed that the two tests measure the same aptitude, but use
different scales.
If a student gets an SAT score that is the 67-percentile, find the
actual SAT score.
SAT score =
Round answer to a whole number.
What would be the equivalent ACT score for this student?
ACT score =
Round answer to 1 decimal place.
If a student gets an SAT score of 1334, find the equivalent ACT
score.
ACT score =
Round answer to 1 decimal place.
Given that, scores on the SAT test are normally distributed with a mean of 992 and a standard deviation of 201.
Let X ~ Normal (992, 201)
Scores on the ACT test are normally distributed with a mean of 19.1 and a standard deviation of 5.1.
Let Y ~ Normal (19.1, 5.1)
a) We want to find, the value of x such that, P(X < x) = 0.67
Therefore, required SAT score = 1080
Now, we wanf to find, the value of y for Z = 0.44
y = (0.44 * 5.1) + 19.1
=> y = 2.244 + 19.1
=> y = 21.344
=> y ≈ 21.3
Therefore, required ACT score = 21.3
b) z-score for x = 1334
Z = (1334 - 992) / 201 = 342 / 201 = 1.70
We want to find, the value of y for Z = 1.70
y = (1.70 * 5.1) + 19.1
=> y = 8.67 + 19.1
=> y = 27.77
=> y = 27.8
Therefore, required ACT score = 27.8