In: Statistics and Probability
Last year, 30% of high school students in a particular county were able to find a summer job. A county official wants to estimate this quantity again this year. She wants to be 95% confident that the margin of error is no larger than 2%. Find the smallest sample size that would allow the official to achieve her goals.
a. |
21 |
|
b. |
2017 |
|
c. |
10 |
|
d. |
474 |
Solution :
Given that,
= 0.30
1 - = 1 - 0.30 = 0.70
margin of error = E =2% = 0.02
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.96 / 0.02)2 * 0.30 * 0.70
= 2017