Question

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3H2S + 2FeCl3 --> 6HCl + Fe2S3. 1.Identify the limiting reagent and calculate the theoretical yield...

3H2S + 2FeCl3 --> 6HCl + Fe2S3.

1.Identify the limiting reagent and calculate the theoretical yield of HCl when 50.0 g of FeCl3 and 40.0 g of H2S are taken.

2.Identify the excess reagent when 50.0 g of FeCl3 and 40.0 g of H2S are taken and determine what mass of the excess reagent remains at the end of the reaction?

Solutions

Expert Solution

1.

Molar mass of

Mass of

Number of moles of

Molar mass of

Mass of

Number of moles of

As per balanced chemical equation, 2 moles of FeCl3 reacts with 3 moles of H2S.

0.308 moles of FeCl3 will react with of H2S. But 1.17 moles of H2S are present. Hence, H2S is excess reagent and FeCl3 is the limiting reagent.

2 moles of FeCl3 gives 6 moles of HCl.0.308 moles of FeCl3 will give

Molar mass of HCl is 36.5 g/mol.

Mass of HCl hat can be obtained (theoretical yield)

2.

Molar mass of

Mass of

Number of moles of

Molar mass of

Mass of

Number of moles of

As per balanced chemical equation, 2 moles of FeCl3 reacts with 3 moles of H2S.

0.308 moles of FeCl3 will react with of H2S. But 1.17 moles of H2S are present. Hence, H2S is excess reagent and FeCl3 is the limiting reagent.

Number of moles of H2S (excess reagent) that remains at the end of the reaction

Molar mass of

Mass of excess reagent (H2S) that remains at the end of the reaction .

queen_honey_blossom answered 3 years ago
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