Question

In: Statistics and Probability

Many people believe that unusual behavior is more likely to occur during a full moon. As...

Many people believe that unusual behavior is more likely to occur during a full moon. As a test for empirical evidence to support this belief, suppose that you categorized the visits of new clients to a community health unit over a one-year period by lunar phases and found the following distribution of visits: Full moon 62, new moon 50, first quarter 60, and third quarter 56.

Answer the following questions:

1. What are the null and alternate hypotheses?

2. What are the expected values for each of the categories?

3. What is the chi-square obtained?

4. What is the critical value?

5. What is your statistical decision? Justify your answer.

6. What is your conclusion?

Solutions

Expert Solution

1) null hypothesis: visits of new clients appear uniformly over a one-year period by lunar phases.

Alternate hypothesis: visits of new clients do not appear uniformly over a one-year period by lunar phases.

2)

expected values for each of the categories =np=228*0.25 =57

3)

applying chi square test:

           relative observed Expected residual Chi square
category frequency Oi Ei=total*p R2i=(Oi-Ei)/√Ei R2i=(Oi-Ei)2/Ei
Full moon 0.250 62.000 57.00 0.66 0.439
new moon 0.250 50.000 57.00 -0.93 0.860
First quarter 0.250 60.000 57.00 0.40 0.158
third quarter 0.250 56.000 57.00 -0.13 0.018
total 1.000 228 228 1.474

chi-square obtained =1.474

4)

for 0.05 level and 3 degree of freedom :crtical value = 7.815

5)

as test statistic is less than critical value we fail to reject null hypotheiss

6)we do not have enough evidence at 0.05 level to conclude that visits of new clients do not appear uniformly over a one-year period by lunar phases.


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