In: Chemistry
The freezing point of ethanol CH3CH2OH is -117.30°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in ethanol is chlorophyll . If 14.52 grams of chlorophyll, C55H72MgN4O5 (893.5 g/mol), are dissolved in 178.5 grams of ethanol ... The molality of the solution is ______ m. The freezing point of the solution is _____ °C.
weight of chlorophyll = 14.52g
gram molecular weight (G.M.Wt) = 893.5g/mole
weight of solvent (ethanol) = 178.5g
molality = W*1000/G.M.Wt * weight of solvent in g
= 14.52*1000/893.5*178.5 = 0.091m
Kf of ethanol = 1.990C/m
i = 1 for nonelectrolyte
Tf = i*m*Kf
= 1*0.091*1.99
= 0.181090C
Tf = solvent ( Tf) - solution ( Tf)
0.18109 = -117.3 - solution(Tf)
-solution ( Tf) = 0.18109+117.3
solution = -117.480C
the freezing point of solution = -117.480C