Question

A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 45 girls in 81​ births, so the sample statistic of 5/9 (five ninths) results in a z score that is 1 standard deviation above 0. Complete parts​ (a) through​ (h) below.

a. Identify the null hypothesis and the alternative hypothesis?

b. What is the value of α​?

α=

​(Type an integer or a​ decimal.)

c. What is the sampling distribution of the sample​ statistic?

Student​ (t) distribution

chi squaredχ2

Normal distribution

d. Is the test​ two-tailed, left-tailed, or​ right-tailed?

Right​-tailed

LeftLeft​-tailed

​Two-tailed

e. What is the value of the test​ statistic?

The test statistic is____.

​(Type an integer or a​ decimal.)

f. What is the​ P-value?

The​ P-value is___.

​(Round to four decimal places as​ needed.)

g. What are the critical​ value(s)?

The critical​ value(s) is/are___.

​(Round to two decimal places as needed. Use a comma to separate answers as​ needed.)

h. What is the area of the critical​ region?

The area is __.​(Round to two decimal places as​ needed.)

Answer 1

Here P-value = 0.1588 > Level of significance = 0.05

therefore we do not reject H0.

Conclusion:

There is not sufficient evidence to support the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5