Question

A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender​ selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 ​births, so the sample statistic of six thirteenths results in a z score that is 1 standard deviation below 0. -What is the null hypothesis and alternative hypothesis -what is the value of alpha -what is the sampling distribution of the sample statistic? -Is the test two-tailed, left tailed or right tailed? -what is the value of the test statistic? -P-value? -What are the critical values? - What is the area of the critical region? How to solve this with TI-83?

Answer 1

By using the TI-83 calculator we have to solve this question.

Claim:  parents use a particular method of gender selection, the proportion of baby girls is less than 0.5.

The null and alternative hypothesis is

H0: P = 0.5

H1: P < 0.5

Level of significance = 0.1

Our test is left tailed because the alternative hypothesis has less than sign.

Ti-83 calculator path is Click on STAT ----->TESTS -------->1-PropZTest ------>Enter values --->

P0: 0.5

x : 78

n: 169

prop: < p0

Calculate

We get

Test statistic z = - 1

P-value = 0.1587

Critical value = 1.28

Test statistic | z | < critical value we fail to reject null hypothesis.

Coclusion:

Parents use a particular method of gender selection, the proportion of baby girls is NOT less than 0.5.