Question

Calculate the mole fraction of solute when 355 g of CO₂ is in 0.409 L of water (density of water is 1.00 g/mL)

Answer 1

Given

mass of CO₂ = 355g

Volume of water = 0.409lit

density of water = 1.00 g/ml

we know

density = mass / volume

then, mass of water = density * volume

                             = 1.00g/ml * 409 ml = 409 g

we know mole fraction of CO₂ = (mass of CO₂) / (mass of CO₂ + mass of water)

                                            = (355 g) / (355g + 409g) = 0.465