In: Statistics and Probability
The town of KnowWearSpatial, U.S.A. operates a rubbish
waste disposal facility that is overloaded if its 5055 households
discard waste with weights having a mean that exceeds 26.96 lb/wk.
For many different weeks, it is found that the samples of 5055
households have weights that are normally distributed with a mean
of 26.64 lb and a standard deviation of 12.56 lb.
What is the proportion of weeks in which the waste disposal
facility is overloaded?
P(M > 26.96) =
Enter your answer as a number accurate to 4 decimal places. NOTE:
Answers obtained using exact z-scores or z-scores
rounded to 3 decimal places are accepted.
Is this an acceptable level, or should action be taken to correct a
problem of an overloaded system?
Solution :
Given that,
mean = = 26.64 lb
standard deviation = = 12.56 lb
n = 5055
= = 26.64 lb
= / n = 12.56 / 5055 = 0.1767
P(M > 26.96) = 1 - P(M < 26.96)
= 1 - P[(M - ) / < (26.96 - 26.64) / 0.1767 ]
= 1 - P(z < 1.811)
Using z table,
= 1 - 0.9649
= 0.0351
Yes, this is an acceptable level because it is unusual for the system to be overloaded. because probability is less than 0.05